How do you make 0.1 N K2Cr2O7?
Answers
Answer:
In acidic medium K2Cr2O7 reacts as follows.
•K2Cr2O7 + 4 H2SO4 =========> K2SO4+ Cr2(SO4)3+ 4H2O +3(O)
•So Equivalent Mass of K2Cr2O7= Mol.Wt/6= 294.186/6= 49.03
•So weigh 49.03/10= 4.903 g of K2Cr2O7 accurately and take in a 1- Litre standard flask and dissolve well with distilled water. Then add distilled water up to the mark and shake well for uniform concentration.
•You have now 0.1N Standard Solution of K2Cr2O7.
•If you want 250 ml or 100 ml of 0.1N K2Cr2O7, then weigh accordingly (4.903/4= 1.224) or (4.903/10= 0.4903) g of K2Cr2O7 and then make in 250 ml or 100 ml standard flasks accordingly.
•You will get 0.1N K2Cr2O7.
Answer:
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