How do you name the point and slope given y=3+2(x−1)?
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Solution:
Convert given equation y=3+2(x-1) into y=mx+c
y = 3+2x-2
=> y = 2x+1
Now,
Slope (m) = 2
y-intercept (c) = 1
Therefore,
Required equation:
y = 2x+1
••••
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Hey.
Refer the below attachment !
Thanks !
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