Question

how do you prepare 0.01 normal sulphuric acid in 500 ml of solution​

Answer 1

3.15 g

For hydrated oxalic acid, (COOH)

2

.2H

2

O, molar mass is 126 g/mol.

Equivalent weight =

2

M

=63

Meq. of oxalic acid =500×0.1=50

E×1000

w

=50

w=

2

126

×50×1000=3.15 g

Hence, mass of oxalic acid required is 3.15 g.

Explanation:

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