Question

How do you prove sin3 theta/ sin theta - cos3 theta/ cos theta = 2

Answer 1

Answer:

cool

Step-by-step explanation:

cool

Answer 2

Answer:

According to de Moivre's identity

sinθ=eiθ−e−iθ2i and

cosθ=eiθ+e−iθ2

so following

a3−b3a−b=a2+ab+b2

ei3θ−e−i3θeiθ−e−iθ=ei2θ+1+e−i2θ

and

ei3θ+e−i3θeiθ+e−iθ=ei2θ−1+e−i2θ

so

ei3θ−e−i3θeiθ−e−iθ−ei