How do you prove that the diagonals pf a parallelogram bisect each other??
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3
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Expert Answer:
ABCD is a parallelogram, diagonals AC and BD intersect at O.
In triangles AOD and COB,
DAO = BCO (alternate interior angles)
AD = CB.
ADO = CBO (alternate interior angles)
AOD COB (ASA)
Hence, AO = CO and OD = OB (c.p.c.t)
Thus, the diagonals of a parallelogram bisect each other.
Answered by
2
Answer:
Step-by-step explanation:
ABCD is a parallelogram, diagonals AC and BD intersect at O
In triangles AOD and COB,
DAO = BCO (alternate interior angles)
AD = CB
ADO = CBO (alternate interior angles)
AOD COB (ASA)
Hence, AO = CO and OD = OB (c.p.c.t)
Thus, the diagonals of a parallelogram bisect each other.
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