How do you prove this trigonometric expression show your work
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take L.H.S
= cos^2θ-sin^2θ (1)
we know that from trig identity sin^2θ+cos^2θ=1
so
cos^2θ=1-sin^2θ value put in (1)
= 1-sin^2θ-sin^2θ
= 1-2sin^2θ
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