Math, asked by sg0329019, 3 months ago

how do you put (2x+1)(3x-5) into a box method to get 6x^2-7x-5

Answers

Answered by AVENGEGAMING

1

Answer:

(2x+1)(3x-5)

first multiply 2x+1 by 3x then 2x+1 by -5x

=2x*3x+2x*-5+1*3x+1*(-5)

=6x^2-10x+3x-5

=6x^2-7x-5

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