How do you simplify (4-5i)(4+5i) and write the complex number in standard form?
Answers
Answered by
0
Answer:
16-25i^2
a^2-b^2=(a+b) (a-b)
4^2-5i^2
=16-25i^2
Answered by
0
Answer:
41
Step-by-step explanation:
(4-5i)(4+5i)=4² - (5i)² .......... (using the identity (a+b)(a-b)=a² - b²)
=16-25( i )²
But i² = -1
∴ (4-5i)(4+5i)=16+25=41
Similar questions