Math, asked by revanth2121, 1 year ago

How do you simplify and write b8(2b)4 with positive exponents?

Answers

Answered by CEOEkanshNimbalkar
0

Answer : 64 b^2

Step by step explanation :

b \times 8 \times (2b) \times 4

Remove unnecessary parenthesis.

 =  > b \times 8 \times 2b \times 4

Calculate the product.

If a term doesn't have an exponent it is considered that the exponent is 1.

 =  > b {}^{1}  \times 8 \times 2b {}^{1}  \times 4

Use rules of multiplication to calculate the expression.

 =  > b {}^{1}  \times 64b {}^{1}

Multiply the terms with the same base by adding their exponents.

 =  > b {}^{1 + 1}  \times 64

Add the numbers

 =  > b {}^{2}  \times 64

Use the commutative property to reorder the terms.

 =  > 64b {}^{2}

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