Math, asked by Twinkle5851, 1 year ago

How do you simplify [x2−xx+5]⋅[x2+5x+4x4−x2]?

Answers

Answered by abhishek0404
0

Answer:

x

+

1

x

4

,

if

x

+

4

0

Explanation:

Step 1: Factor both the numerator and denominator.

x

2

+

5

x

+

4

x

2

16

=

(

x

+

1

)

(

x

+

4

)

(

x

4

)

(

x

+

4

)

Step 2: Cancel common factors.

(

x

+

1

)

(

x

+

4

)

(

x

4

)

(

x

+

4

)

=

x

+

1

x

4

,

if

x

+

4

0

Why write this "if

x

+

4

0

" part? Because in the original quotient, if

x

+

4

=

0

(that is, if

x

=

4

), then the denominator would equal zero, and division by zero is undefined.

On its own,

x

+

1

x

4

does not give the same problem when

x

=

4

.

Since we want our simplified expression to reflect the original one in its entirety, we make sure it has all the same restrictions, including

x

+

4

0

.

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