Question

How do you solve 0x–8y=−16 and −8x+2y=36?

Answer 1

Answer:

$0x - 8y = - 16 \\ \\ - 8y = - 16 \\ \\ y = \frac{16}{8} \\ \\ \bf y = 2$

Putting the value of y in (ii)

$- 8x + 2y = 36 \\ \\ - 8x + 2 \times 2 = 36 \\ \\ - 8x = 36 - 4 \\ \\ - 8x = 32 \\ \\ x = \frac{ - 32}{8} \\ \\ \bf x = - 4$

Thanks....!!

Answer 2

Answer:

Step-by-step explanation:

0x - 8y = -16

-8y = -16

Y = -16/-8 = 2

-8x + 2y = 36

Putting value of y

-8x + 2(2) = 36

-8x + 4 = 36

-8x = 36-4

-8x = 32

X = 32/-8 = -4

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