Math, asked by SrijeetaRay9066, 1 year ago

How do you solve 11(4−6y)+5(13y+1)=9?

Answers

Answered by LilyWhite
0

11(4-6y) + 5(13y+1) = 9

{ 44 - 66y } + { 65y + 5 } = 9

44 - 66y + 65y + 5 = 9

44 - 1y + 5 = 9

49 - 1y = 9

- 1y = 9 - 49

- 1 y = - 40

Y = - 40 / - 1

Y = 40

Answered by Anonymous
32

hlo mate here is ur answer

11(4-6y)+5(13y+1)=9

(44-66y)+(65y+5)=9

44-66y+65y+5=9

44-1y+5=9

49-1y=9

-1y=9-49

-1y=-40

y=-40/-1

y=40

HOPE THIS WILL HELP U

@Anayaprincess

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