Question

How do you solve 11c−2(2c+1)=3(c−6)?

Answer 1

Answer:

Step-by-step explanation:

11c-2(2c+1)= 3(c-6)

11c -(2x2c)-(2x1)= (3xc)-(3x6)

11c -4c-2=3c-18

11c-4c-3c=-18+2

11c-7c=-16

4c=-16

c=-16/4

c=-4