Question

How do you solve 15x2−1=4x−1−3x+1?

Answer 1

Solution:

15x²-1=4x-1-3x+1

=> 15x²-1=4x-3x-1+1

=> 15x²-1=x

=> 15x²-x-1=0

Compare this with ax²+bx+c=0

,we get

a = 15, b = -1 , c = -1

Discreminant (D) =b²-4ac

= (-1)²-4×15×(-1)

= 1+60

= 61

By Quadratic Formula:

x =[(-b±√D)/(2a)]

= [-(-1)±√61]/(2×15)

= (1±√61)/30

Therefore,

x = (1+√61)/30

or

x = (1-√61)/30

••••

Answer 2

Hey!

Refer the below attachment !

Thanks !