Question

How do you solve 2(1−b)−1=−3(b−3)?

Answer 1

Answer:

$2(1 - b) - 1 = - 3(b - 3) \\ \\ 2 - 2b - 1 = - 3b + 9 \\ \\ - 2b + 3b = 9 - 2 + 1 \\ \\ \fcolorbox{red}{yellow}{ \bf b = 8}$

Answer 2

$2(1 - b) - 1 = - 3(b - 3)$

$2 - 2b - 1 = - 3b + 9$

$1 - 2b = 9 - 3b$

$1 - 2b + 3b = 9$

$1 + b = 9$

$b = 9 - 1$

$b = 8$