Question

How do you solve 2−3[x−2(x+1)]=x−[2−(x−3)]?

Answer 1

Answer:

x-[2-(x-3)]=2-3[x-2(x+1)]

x-(2-x+3)=2-3x^[2]+x-2x-2]

x-(-x+5)=2-3x^[2]-3x+6x+6

2x+5=-3x^[2]+3x+8

take all on left side

3x^[2]-3x+2x-8+5=0

3x^[2]-x-3 is your answer.

Answer 2

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