How do you solve −2(h−1)−3(h+4)=0?
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✔✔-2(h-1)-3(h+4)=0
✔✔-2h+2-3h-12=0
✔✔-5h-10=0
✔✔h=2
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-2(h-1)-3(h+4)=0
-2h+2-3h-12=0
-5h-10=0
h=2
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