Question

How do you solve 2(x−1)+3=x−3(x+1)?

Answer 1

Answer:

$\sf 2(x - 1) + 3 = x - 3(x + 1) \\ \\\sf 2x - 2 + 3 = x {}^{2} + x - 3x - 3 \\ \\ \sf 2x + 1 = x {}^{2} - 2x - 3 \\ \\\sf x {}^{2} - 2x - 2x - 3 - 1 = 0 \\ \\ \sf x {}^{2} - 4x - 4 = 0 \\ \\\sf x {}^{2} - 2x - 2x - 4 = 0 \\ \\ \sf x(x - 2) - 2(x - 2) = 0 \\ \\ \sf (x - 2)(x - 2) = 0 \\ \\ \bf x = 2 \: or \: = 2$