How do you solve 2(y+2)+y=19−(2y+3)?
Answers
Answered by
0
given 2(y+2)+y=19-(2y+3)
2y+4+y=19-2y-3
3y+4=16-2y
3y+2y=16-4
5y=12
y=12/5
hope this answer will make u happy
thulasisrivyshnavi1:
may be this is the correct answer
if it is wrong ...sorry for that
Answered by
0
Answer:2.4
Step-by-step explanation:2(y+2)+y=19-(2y+3)
2y+4+y=19-2y-3
2y+4+y=16-2y
2y+4+y+2y=16
5y+4=16
5y=16-4
5y=12
y=12/5
y=2.4
Similar questions