How do you solve (2x−1)2+｜2x−1｜−12=0?
Answers
Answered by
1
(2x-1)2 + | 2 x-1 | = 12
here mode is taken of the second term so it is taken to be +ve
Now simplifying the terms we get
4x - 2 + 2x - 1 = 12
6x - 3 = 12
6x = 15
x = 15÷6
x = 5/2
x = 2.5
here mode is taken of the second term so it is taken to be +ve
Now simplifying the terms we get
4x - 2 + 2x - 1 = 12
6x - 3 = 12
6x = 15
x = 15÷6
x = 5/2
x = 2.5
Answered by
0
(-3) 2+2-12=
-3multiply by 2+2-12
6+2-12
8-12
-4 answer
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