How do you solve 2x−3(1−2x)<31?
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2x _3 +6x = 31
8x _3 = 31
8x =31 + 3
8× = 34
x = 34/8
x = 4
On filling value of x,
2(4)_3+6(4)
=8_3 +24
=5+24=29 hence 31 is greater then 2x_3(1 _2x)
8x _3 = 31
8x =31 + 3
8× = 34
x = 34/8
x = 4
On filling value of x,
2(4)_3+6(4)
=8_3 +24
=5+24=29 hence 31 is greater then 2x_3(1 _2x)
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