How do you solve 3(x2−2x+5)−2(3x−5)=4(x2−x−5)−(x2+3)?
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Heya...,
Your answer is here..,
3(x2-2x+5) -2(3x-5) = 4(x2- x-5)-(x2 +3)
= 3x2-6x+15-6x+10 = 4x2-4x-20-x2+3
= 3x2-6x-6x+10+15 = 4x2-x2-4x+3-20
= 3x2 -12x+25 = 3x2 - 4x+ 17
= 3x2-3x2 -12x+4x +25-17
=0x2 - 8x + 8
= -8x = -8
= x = -8/-8
x = 1
hope its helpful to you.....
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