Math, asked by juhishah6848, 1 year ago

How do you solve 3y=−2x,y=x−5 by substitution?

Answers

Answered by infinity1020
2

{\red{\huge{\bf{Hey}}}}

3y+2x=0

3(x-5)+2x=0

3x-15+2x=0

5x-15=0

5x=15

X=3✓✓

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