Question

How do you solve 4x2+3x−10−1x2−x−6=3x2−x−12?

Answer 1

4×2+3x-10-1×2-x-6=3×2-x-13

8+2x-10-2-6=6-x-13

8+2x-18=-7-x

-10+2x=-7-x

2x+X=10-7

3x = 3

X =3÷3

X = 1