Math, asked by mkaneesh865, 1 year ago

How do you solve 4y−1+23=6y−1?

Answers

Answered by ploughcity49
0

4y-1+23=6y-1

=4y+22=6y-1

=4y+22+1=6y

=4y-6y=-23

=-2y=-23

=y=23/2=11.5

HOPE THIS HELPS....

Similar questions