Question

How do you solve 4y2−3(y−4)=4y(y−1)+3y?

Answer 1

here is your answer mate.

please please please mark me as brain list if my answer helps you

Answer 2

Answer:

 y = 6

Step-by-step explanation:

                   4y^2 - 3(y-4)   =   4y(y-1) + 3y

                   4y^2 - 3y + 12 =   4y^2 - 4y + 3y

 4y^2 - 4y^2 -3y + 4y - 3y =    -12

                             y - 3y     =    -12

                                  -2y    =   -12

                                       y   =   12/2

                                        y  = 6  

     

Hope it will help you

Plzzz. mark it as brainliest