Question

How do you solve 5x²−6x–3=0?

Answer 1

$5x {}^{2} - 6x - 3 = 0$

Solve the quadratic equation using quadratic formula.

$= > x = \frac{ - ( - 6) + - \sqrt{( - 6) {}^{2} - 4 \times 5 \times ( - 3) } }{2 \times 5}$

Evaluate the power. Use rules of multiplication to calculate the expression. Multiply the numbers in the denominator.

$= > x = \frac{6 + - \sqrt{36 + 60} }{10}$

Add the numbers in the numerator.

$= > x = \frac{6 + - \sqrt{96} }{10}$

Simplify the radical.

$= > x = \frac{6 + - 4 \sqrt{6} }{10}$

Separate the solutions.

$x = \frac{6 + 4 \sqrt{6} }{10}$

$x = \frac{6 - 4 \sqrt{6} }{10}$

Simplify both the expressions.

$x = \frac{3 + 2 \sqrt{6} }{5}$

$x = \frac{3 - 2 \sqrt{6} }{5}$