Math, asked by kyurem6500, 1 year ago

How do you solve 6sin2x+5=8 for 0≤x≤π?

Answers

Answered by mohan185

0

6sin2x+5=8

6sin2x=8-5

6sin2x=3

sin2x=3/6

sin2x=1/2

sin2x=sin30°(sin30°=1/2)

we remove the sin on both sides

2x=30°

x=30°/2

x=15°

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