Question

How do you solve 6x=−x²−8?

Answer 1

$x {}^{2} + 6x + 8 \\ x {?}^{2} + 4x + 2x + 8 \\ x(x + 4) + 2(x + 4) \\ (x + 4)(x + 27) = 0 \\ x + 4 = 0 \\ x = 0 - 4 \\ x = - 4\\ x + 2 = 0 \\ x = 0 - 2 \\ x = - 2 \\ x = - 2and - 4$