How do you solve 7(k+2)+5≥5?
Answers
Answered by
0
7(k+2)+5≥5
7k +14+5 ≥5
7k +19 ≥5
Subtracting 19 from both sides,
7k+19-19 ≥5-19
7k ≥ - 14
Dividing by 7 on both sides,
K ≥-2
Answered by
0
Answer:
7(k+2)+5≥5
=>7(k+2)≥0
=>k+2≥0
=>k≥-2
Hpe it hlps u
Similar questions