How do you solve 7x+6−2(5+3t2)=5t−11?
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Answer:
x=(6t2+5t-7)/7
Step-by-step explanation:
7x+6−2(5+3t2)=5t−11
7x+6− 10-6t2=5t-11
7x-4=6t2+5t-11
7x=6t2+5t-11+4
7x=6t2+5t-7
x=(6t2+5t-7)/7
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