Question

How do you solve the equation 2x2+5x−3=0 by using the quadratic formula?

Answer 1

this is the answer

answer is 1/2 and 3

Answer 2

Given

$2 {x}^{2} + 5x - 3 = 0 \\ \\ here \: \\ a = 2 \\ b = 5 \\ c = - 3 \\ \\ x = \frac{ - b + - \sqrt{ ({b})^{2} - 4ac } }{2a} \\ \\ x = \frac{ - 5 + - \sqrt{( {5)}^{2} - 4 \times 2 \times ( - 3) } }{2 \times 2} \\ \\ x = \frac{ - 5 + - \sqrt{25 + 24 } }{4} \\ \\ x = \frac{ - 5 + - \sqrt{49} }{4} \\ \\ so \\ x = \frac{ - 5 + \sqrt{49} }{4} \\ x = \frac{ - 5 + 7}{4} \\ x = \frac{2}{4} = \frac{1}{2} \\ \\ and \: \\ x = \frac{ - 5 - 7}{4} \\ = > x = \frac{ - 12}{4} \\ = > x = - 3$