Question

How do you solve the equation: −32y2−24y=0?

Answer 1

Solution:

-32y²-24y = 0

Take (-8y) common, we get

=> -8y( 4y + 3 ) = 0

=> -8y = 0 or 4y+3=0

=> y = 0 or 4y = -3

=> y = 0 or y = -3/4

Therefore,

y = 0 or y = -3/4

••••