How do you solve the following system: y=34x+3,3x−3y=2?
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Heya...,
Your answer is here...,
-34x + y = 3....(1)×3
3x - 3y = 2...(2)
-102x + 3y = 9
+
3x - 3y = 2
-99x. = 11
x = 11/-99
x = 1/-9
put x = -1/9 in equation..(2)
3x - 3y = 2
3×(-1/9) -3y = 2
-1/3 - 3y = 2
-1-9y = 2
-9y = 2+1
-9y = 3
y = 3/-9
y = 1/-3
y = -1/3
therefore solution of (x,y) = (-1/9, -1/3).
hope its will helpful to you....
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