Question

How do you solve the following system: y=34x+3,3x−3y=2?

Answer 1

Heya...,

Your answer is here...,

-34x + y = 3....(1)×3

3x - 3y = 2...(2)

-102x + 3y = 9

+

3x - 3y = 2

-99x. = 11

x = 11/-99

x = 1/-9

put x = -1/9 in equation..(2)

3x - 3y = 2

3×(-1/9) -3y = 2

-1/3 - 3y = 2

-1-9y = 2

-9y = 2+1

-9y = 3

y = 3/-9

y = 1/-3

y = -1/3

therefore solution of (x,y) = (-1/9, -1/3).

hope its will helpful to you....

Answer 2

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