Question

How do you solve the inequality 3x2≤11x+4 and write your answer in interval notation?

Answer 1

Answer: - $\frac{1}{3}$ $\leq$ x $\leq$ 4

Step-by-step explanation:

3x^2 < 11x+4

3x^2 = 11x + 4

3x^2 - 11x - 4 = 0

a = 3, b = -11, c = -4

D = (-11)^2 - 4 * 3 * -4 = 169, square root = 13

x = (11 + 13) / (2 * 3) = 4

x = (11 - 13) / (2 * 3) = - $\frac{1}{3}$

Therefore - $\frac{1}{3}$ $\leq$ x $\leq$ 4