Question

How do you solve the system 2x+3y=12 and 4x−3y=6?

Answer 1

see= 2x+3y = x +y =2+3=5

so, 5xy

Answer 2

2x+3y=12 ...

....

3y=12-2x

y = 12-2x/3

By putting different values of x..

Put x = 0 , 1, 2....

4x - 3y = 6 .....

....

4x = 6 + 3y

x = 6+3y/4

By putting different values of y..

Put y = 0, 1 , 2 .....