How do you solve the system 3x - 2y = 10 and 5x + 3y = 4?
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[3x-2y=10]*3 ...........(1)
[5x+3y=4]*2 .............(2)
Now after multiplying 1 by 3 and second by 2
9x-6y=30...........(1)
10x+6y=8...........(2)
Now add eqn
19x=38
x=2
y=-(4)
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