How do you solve the system 3x−2y=11 and x−12y=4 using substitution?
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Hey mate
here is your answer
from second eqn
we get x = 4+12y
put these in first eqn
we get
3(4+12y)–2y = 11
by solving
we get the values of y and x are respectively -1/34
and 62/17
HOPE THIS ANSWER
HELPS YOU
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