Question

How do you solve the system of equations 14x−9y=2 and x−9y=−50?

Answer 1

Answer:

let naming the equations as

14x−9y=2  .....(1)

x−9y=-50   ....(2)

Subtracting equation (2) from equation (1) we get

13x=52

x=4

By putting value of x in equation (2) we get

4-9y=-50

9y=54

y=6.

So x=4 and y=6 are required solutions.

Step-by-step explanation:)

Answer 2

Hi mate your answer is here:

Answer: X = 4, y = 6,

step by step explanation:

14x - 9y = 2.........(1)

X - 9y = -50........(2)

equation (1) - equation (2)

14x -9y - x + 9y = 2 - (-50)

13x = 52

X = 4

on putting the value of x in equation (1),

14×4 - 9y = 2

56 - 9y = 2

-9y = 2-56

-9y = -54

y = 6

so, X= 4 and y = 6

HOPE THIS HELPS YOU