Question

How do you solve the system of equations 5x−3y=1 and 9x−4y=6?

Answer 1

Solution:

Given system of equations are,

5x-3y = 1 ------(1)

9x-4y = 6 ------(2)

multiply (1) by 4 and ,

multiply (2) by 3 , we get

20x-12y = 4 ----(3)

27x-12y = 18 ---(4)

Subtract (3) from (4) , we get

7x = 14

=> x = 14/7

=> x = 2

Substitute x=2 in equation (1),

we get

5×2 - 3y = 1

=> 10 - 3y = 1

=> -3y = 1 - 10

=> -3y = -9

=> y = (-9)/(-3)

=> y = 3

Therefore,.

x = 2 ,

y = 3

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