Question

How do you solve the system q=12p−7 and −2p−q=2 by substitution?

Answer 1

q=12p-7

-2p-q=2

-2p-(12p-7)=2

-2p-12p+7=2

-14p+7=2

7-2=14p

5=14p

p=5/14

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Answer 2

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