Question

How do you solve the system using elimination 3a+b=−1 and −3a+b=5?

Answer 1

I hope it will be answer of your question

Answer 2

3a+b+(-3a+b)=-1+5

3a+b-3a+b =4

2b=4

b=4/2

b=2

then put value of "b" in first equation

3a+b=-1

3a+2=-1

3a=-1-2

3a=-3

a=-3/3

a= -1

answer

a=-1, b=2