Question

How do you solve the system using elimination 3y−z=−6 and −3y−z=6?

Answer 1

3y-z=-6____(1)

-3y-z=6____

3y+z=-6_____(2)

from (1) and (2)

3y-z=-6_______(1)

3y+z=-6________(2)

__________________

6y=-12

y=-12/6

y=-2

y=-2 in equation (1)

3y-z=-6

3 (-2)-z=-6

-6-z=-6

-z=-6+6

-z=0

z=0

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