Math, asked by vedika6159, 10 months ago

How do you solve the system w+4x+3y−11z=42 , 6w+9x+8y−9z=31 and −5w+6x+3y+13z=2, 8w+3x−7y+6z=31?

Answers

Answered by Nishkarshkumar
0

1+4+3-11 (w+x+y+z)=42

-7 (w+x+y+z)=42

w+x+y+z =42 -7 =35

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