Question

How do you solve the system x−2y=3 and 4x−8y=12 using substitution?

Answer 1

$x-2y=3 \: \: \: \: \: \: \: \: 4x - 8y = 12 \\ x = 3 + 2y \\ 4x - 8y = 12 \\ 4(3 + 2y) - 8y = 12 \\ 12 + 8y - 8y = 12 \\ = 0$

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