Question

How do you solve the system x−5y=2 and 9x+8=32y?

Answer 1

x-5y=2---------(1)
9x-32y=-8--------(2)
multiplying eq^n no.1 by 9
9x-45y=18

subtracting eq^n no. 2 from 3
-7y=-26
y=26/7
put y=26/7 in eq^n no. 1
x-5×26/7=2
x-130/7=2
x-130=2×7
x-130=14
x=14+130
x=144

(x,y)=(144,26/7) is the ans of ur q.