Question

How do you solve the system y = -3x + 6 and 3x-y = 6?

Answer 1

Answer:

X=2 and Y=0

Step-by-step explanation:

3x+y=6........(1)

3x-y=6.........(2)

x=2

substitute x=2 in equation (1)

6+y=6

y=0

Answer 2

Solution:

y = -3x+6 ----(1)

3x-y = 6 ----(2)

Substitute (1) in equation (2) ,we get

3x - (-3x+6) = 6

=> 3x + 3x - 6 = 6

=> 6x = 6+6

=> 6x = 12

=> x = 12/6

=> x = 2

Now , x = 2 in equation (1) , we get

y = -3×2 + 6

=> y = -6 +6

=> y = 0

Therefore,

x = 2 , y = 0

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