Question

how do you solve this problem?

Answer 1

Hey mate!

Here's your answer!!

Let speed of stream be v and speed of motorboat be u.

Now distance moved by boat in 1
hour = (u+v) × 1=u+v

total time is = 6/v

speed of boat when it turns back=u-v
=>u+v-6=(u-v)(6/v -1)
solving for v we get,
➡ v=3 km/hr
$hope \: it \: helps \: you..$
✌ ✌

Answer 2

heya....


Let x km/minute be the velocity of flow 

                         and speed of boat in still water= y km/minute

let after time=t minutes it passes the raft 

The travel time of raft is (60+t) minutes

       and the distance traveled is (60+t)*x = 6

                                             t = 6/x-60

From the question 60(x+y) - t(y-x) = 6 

                           60x + 60y - (6/x - 60)(y - x) = 6

                       ⇒  60x + 60y - 6y/x + 60y + 6 - 60x = 6

                       ⇒ 120y - 6y/x=0

                       ⇒  20y=y/x

                           x=1/20=1/20 km/minute

                                       = 3km/hr

tysm.#gozmit