Math, asked by sdkjack1279, 10 months ago

How do you solve using elimination of −3x+4y=−11 and −5x−2y=−27?

Answers

Answered by sultan85
0

-3x+4y=-11

sigh change

3x-4y=11_______(1)

-5x-2y=-27 sigh changed

5x+2y=27__________(2)

from ( 1 ) and ( 2 )

2(3x-4y=11)_______(1)

4(5x+2y=27)______(2)

____________________

6x-8y=22________(1)

20x+8y=108_______(2)

______________________

26x=130

x=130/26

x=5

put x=5 in equation ( 1 )

3x-4y=11

3(5)-4y=11

15-4y=11

-4y=11-15

-4y=-4

y=1

hence proof

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