Math, asked by vijaynegisoala7644, 11 months ago

How do you solve x+1x−3=4−12x2−2x−3?

Answers

Answered by CEOEkanshNimbalkar
0

Answer: x = 1/7

Step by step explanation :

x + 1x - 3 = 4 - 12x \times 2 - 2x - 3

Cancel equal terms on both sides of the equation.

 =  > x + 1x = 4 - 12x \times 2 - 2x

When the term has a coefficient of 1, it doesn't have to be written.

 =  > x + x = 4 - 12x \times 2 - 2x

Calculate the product by multiplying the numbers.

 =  > x + x = 4 - 24x - 2x

Collect the like terms by adding their coefficients.

 =  > 2x = 4 - 24x - 2x

Collect the like terms by calculating the sum or difference of their coefficients.

 =  > 2x = 4 - 26x

Move variable to the left side and change its sign.

 =  > 2x + 26x = 4

Collect the like terms by adding their coefficients.

 =  > 28x = 4

Divide both sides of the equation by 28

 =  > x =  \frac{1}{7}

 =  >  x = 7 {}^{ - 1}

Attachments:
Similar questions